#analyticcontinuation
Live, measured metrics for the hashtag #analyticcontinuation from the open social web. Every number carries a named source and the time it was fetched. Nothing is estimated.
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Day-by-day usage
measured · mastodon.online (Mastodon public tags API) · fetched 2026-10-24 00:45 UTC0 uses by 0 unique accounts across the window. Real per-day counts, not estimates. Newest bar is today so far.
Related hashtags
measured · mastodon.online (Mastodon public search API) · fetched 2026-10-24 00:45 UTCNo related tags with measured usage found for #analyticcontinuation.
Live pulse
measured · mastodon.online (Mastodon tag timeline) · fetched 2026-10-24 00:45 UTCEverything below is measured over the latest 6 public posts (spanning ~7133 hours).
Posting hours (UTC)
Languages: English (6)
Avg boosts / post: 0
Top of the latest posts
@zvavybir It does diverge. It has no sum. However, the uniquely valued #Riemann #ZetaFunction can be analytically continued into the left half-plane where we find zeta(-1)=-1/12 (which 'looks like' 1+2+...). #Cesàro #summation will get you
For all \( a > 0 \) we have \[ \int_{-\infty}^\infty e^{-a x^2} = \sqrt{\frac{\pi}{a}} \]. Let's ignore the condition on \( a \) and say \( a \) is \( -1 \), then we have \[ \int_{-\infty}^\infty e^{x^2} = \sqrt{\pi} i \]. The left side obv
zvavybir :palestina: :masked: :trans_disabled_bi: :Green:@[email protected]♥ 0↻ 02024-06-20 11:09 UTCView post →A representation of \(18\) using an analytic continuation of the Dirichlet series and the numbers \(0, 1,2,3,4,5,6\). \[18=\left|\dfrac{1}{\zeta^2(0)}\left(\dfrac{\mathcal{H}(-6)}{\zeta(-5)}-\dfrac{\mathcal{H}(-2)}{\zeta(-1)}\right)\dfrac{\
#analyticcontinuation across platforms
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Every number above is measured from a named public API at the shown fetch time. Nothing is estimated or extrapolated. Platforms that lock their data behind paid APIs are not shown. Agents: the same numbers, as JSON, at /api/hashtags/analyticcontinuation